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-5t^2+35t-12=0
a = -5; b = 35; c = -12;
Δ = b2-4ac
Δ = 352-4·(-5)·(-12)
Δ = 985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{985}}{2*-5}=\frac{-35-\sqrt{985}}{-10} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{985}}{2*-5}=\frac{-35+\sqrt{985}}{-10} $
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